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Question

Physics Question on Atoms

Consider an electron in a hydrogen atom, revolving in its second excited state (having radius 4.65?4.65\,?). The de-Broglie wavelength of this electron is :

A

12.9 ?

B

3.5 ?

C

9.7 ?

D

6.6 ?

Answer

9.7 ?

Explanation

Solution

2πrn=nλn2\pi r_n \, = \, n \lambda_n
λ3=2π(4.65×1010)3\lambda_3 \, = \, \frac{2 \pi (4.65 \times 10^{-10})}{3}
λ3=9.7?\lambda_3 = 9.7\, ?