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Question

Physics Question on Electromagnetic waves

Consider an electromagnetic wave propagating in vacuum. Choose the correct statement :

A

For an electromagnetic wave propagating in +y+y direction the electric field is E=12Eyz(x,t)z^\vec{E}=\frac{1}{\sqrt{2}} E_{y z}(x, t) \hat{z} and the magnetic field is B=12Bz(x,t)y^\vec{ B }=\frac{1}{\sqrt{2}} B _{ z }( x , t ) \hat{ y }

B

For an electromagnetic wave propagating in +y+y direction the electric field is E=12Eyz(x,t)y^\vec{E}=\frac{1}{\sqrt{2}} E_{y z}(x, t) \hat{y} and he magnetic field is B=12Byz(x,t)z^\vec{ B }=\frac{1}{\sqrt{2}} B _{ yz }( x , t ) \hat{ z }

C

For an electromagnetic wave propagating in +x+ x direction the electric field is E=12Eyz(y,z,t)(y^+z^)\vec{ E }=\frac{1}{\sqrt{2}} E _{ yz }( y , z , t )(\hat{ y }+\hat{ z }) and the magnetic field is B=12Byz(y,z,t)(y^+z^)\vec{ B }=\frac{1}{\sqrt{2}} B _{ yz }( y , z , t )(\hat{ y }+\hat{ z })

D

For an electromagnetic wave propagating in +x+x direction the electric field is E=12Eyz(x,t)(y^z^)\vec{E}=\frac{1}{\sqrt{2}} E_{y z}(x, t)(\hat{y}-\hat{z}) and eh magnetic field is B=12Byz(x,t)(y^+z^)B =\frac{1}{\sqrt{2}} B _{ yz }( x , t )(\hat{ y }+\hat{ z })

Answer

For an electromagnetic wave propagating in +x+x direction the electric field is E=12Eyz(x,t)(y^z^)\vec{E}=\frac{1}{\sqrt{2}} E_{y z}(x, t)(\hat{y}-\hat{z}) and eh magnetic field is B=12Byz(x,t)(y^+z^)B =\frac{1}{\sqrt{2}} B _{ yz }( x , t )(\hat{ y }+\hat{ z })

Explanation

Solution

If wave is propagating in xx direction, E&B\vec{E} \,\& \,\vec{B} must be functions of (x,t)&(x, t) \& must be in yzy-z plane.