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Question: Consider a tank made of glass (refractive index \( 1.5 \) ) with a thick bottom. It is filled with a...

Consider a tank made of glass (refractive index 1.51.5 ) with a thick bottom. It is filled with a liquid of refractive index μ\mu . A student finds that, irrespective of what the incident angle ii (see figure) is for a beam of light entering the liquid, the light reflected from the liquid glass interface is never completely polarized. For this to happen, the minimum value of μ is

(A) 35\dfrac{3}{{\sqrt 5 }}
(B) 53\dfrac{5}{{\sqrt 3 }}
(C) 53\sqrt {\dfrac{5}{3}}
(D) 43\dfrac{4}{3}

Explanation

Solution

For finding out the minimum value of the refractive index, we need to use the relation between Brewster angle and the critical angle which is given as sin c<sin ib  sin{\text{ }}c < sin{\text{ }}{i_{b\;}} . Brewster angle is an angle of incidence at which light with a particular polarization is perfectly transmitted through a transparent dielectric surface, with no reflection.

Formula used:
sin c<sin ib  sin{\text{ c}} < sin{\text{ }}{i_{b\;}}
 sin90=μsinc sinc=1μ \ sin90 = \mu \sin c \\\ \Rightarrow sinc = \dfrac{1}{\mu } \\\
Where, the critical angle be  c{\text{ c}} , the Brewster angle be  ib  {\text{ }}{i_{b\;}} ,  μ{\text{ }}\mu is the refractive index.

Complete step by step solution:
Let us consider the critical angle be c, the Brewster angle be ib.
The relation comes between the critical angle and the Brewster angle is,
sin c<sin ib  sin{\text{ }}c < sin{\text{ }}{i_{b\;}}
For the ray travelling from air to liquid,
sin90=μsincsin90 = \mu \sin c
Now the value of sin90sin90 is 1 so we get
sinc=1μsinc = \dfrac{1}{\mu }
Since, we know that,
tanib=μ0rel\tan {i_b} = {\mu _{{0_{rel}}}}
And,
sin c<sin ib  sin{\text{ }}c < sin{\text{ }}{i_{b\;}}
Then substituting the values in the equation we get,
1μ<1.5μ2+(1.5)2\Rightarrow \dfrac{1}{\mu } < \dfrac{{1.5}}{{\sqrt {{\mu ^2} + {{(1.5)}^2}} }}
Thus, after simplification, we get,
μ<35\Rightarrow \mu < \dfrac{3}{{\sqrt 5 }}
Hence, the correct answer is option A.

Note:
There are numerous applications of Brewster angle in real life. It includes,
-Polarized sunglasses use the principle of Brewster's angle to reduce glare from the sun reflecting off horizontal surfaces such as water or road.
-Photographers use the same principle to remove reflections from water so that they can photograph objects beneath the surface.
-Brewster angle prisms are used in laser physics. The polarized laser light enters the prism at Brewster's angle without any reflective losses.
-In surface science, Brewster angle microscopes are used in imaging layers of particles or molecules at air-liquid interfaces.