Solveeit Logo

Question

Physics Question on System of Particles & Rotational Motion

Consider a system of two particles having masses m1m_1 and m2m_2. If the particle of mass m1m_1 is pushed towards the mass centre of particles through a distance 'dd', by what distance would be particle of mass m2m_2 move so as to keep the mass centre of particles at the original position ?

A

m1m1+m2d\frac{m_1}{m_1+m_2}d

B

m1m2d\frac{m_1}{m_2}d

C

d

D

m2m1d\frac{m_2}{m_1}d

Answer

m1m2d\frac{m_1}{m_2}d

Explanation

Solution

m1r1=m2r2(1)m _{1} r _{1}= m _{2} r _{2} \ldots(1)
m1(r1d)=m2(r2d)..(2)m _{1}\left( r _{1}- d \right)= m _{2}\left( r _{2}- d ^{\prime}\right) \ldots . .(2)
from (1) and (2) we get
d=m1m2dd' =\frac{ m _{1}}{ m _{2}} d