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Question: Consider a solid sphere of radius R which has volume charge density given by the expression $\rho = ...

Consider a solid sphere of radius R which has volume charge density given by the expression ρ=ρ0(1rR)\rho = \rho_0 \left( 1 - \frac{r}{R} \right) where ρ0\rho_0 is a constant and rr is the distance from the center. There is no charge outside the sphere. Consider potential at infinite distance from the solid sphere to be zero. What is the distance of a point from center of solid sphere where electric field is maximum?

A

R4\frac{R}{4}

B

R3\frac{R}{3}

C

2R3\frac{2R}{3}

D

R2\frac{R}{2}

Answer

2R3\frac{2R}{3}

Explanation

Solution

To find the point where the electric field is maximum, we need to:

  1. Calculate the electric field inside the sphere (rRr \le R) using Gauss's Law. This involves finding the enclosed charge Qenclosed(r)Q_{enclosed}(r) and then applying Gauss's Law to find E(r)E(r).

  2. Calculate the electric field outside the sphere (r>Rr > R) using Gauss's Law with the total charge QtotalQ_{total}.

  3. Find the maximum of E(r)E(r) within the sphere (0rR0 \le r \le R) by taking the derivative of E(r)E(r) with respect to rr, setting the derivative to zero, and solving for rr.

  4. Compare the value of E(r)E(r) at the critical point found in step 3 with the value at the boundary r=Rr = R and consider the behavior for r>Rr > R to determine the absolute maximum.

The electric field is maximum at r=2R3r = \frac{2R}{3}.