Question

Consider a parallel plate capacitor of $10\,\mu F$ (micro-farad) with air filled in the gap between the plates. Now one-half of the space between the plates is filled with a dielectric of dielectric constant $4$, as shown in the figure. The capacity of the capacitor changes to

• A. $25\,\mu F$
• B. $20\, \mu F$
• C. $40\,\mu F$
• D. $5\, \mu F$

Answer 1

Answer: (A)

$25\,\mu F$

Answer 2

$C_{1}=\frac{\varepsilon_{0}\left(\frac{A}{4}\right)}{d},$ $C_{2}=\frac{K \varepsilon_{0}\left(\frac{A}{2}\right)}{d}$