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Question: Consider a non-zero complex number z satisfying the equation $|z+\frac{2}{\overline{z}}|=3$. Then th...

Consider a non-zero complex number z satisfying the equation z+2z=3|z+\frac{2}{\overline{z}}|=3. Then the sum of all possible values of z|z| is

A

1

B

2

C

3

D

4

Answer

3

Explanation

Solution

Let z=r|z|=r. Since zz is a non-zero complex number, r>0r>0. We use the property z=z2z=r2z\overline{z} = \frac{|z|^2}{z} = \frac{r^2}{z}. Substituting this into the given equation, we get z+2r2/z=3|z+\frac{2}{r^2/z}| = 3, which simplifies to z(1+2r2)=3|z(1+\frac{2}{r^2})|=3. Using the property ab=ab|ab|=|a||b|, we have z1+2r2=3|z||1+\frac{2}{r^2}|=3. Since r>0r>0, 1+2r21+\frac{2}{r^2} is a positive real number, so 1+2r2=1+2r2|1+\frac{2}{r^2}| = 1+\frac{2}{r^2}. The equation becomes r(1+2r2)=3r(1+\frac{2}{r^2})=3. Distributing rr, we get r+2r=3r+\frac{2}{r}=3. Multiplying by rr (since r0r \neq 0), we obtain r2+2=3rr^2+2=3r, which rearranges to the quadratic equation r23r+2=0r^2-3r+2=0. Factoring this equation gives (r1)(r2)=0(r-1)(r-2)=0. Thus, the possible values for r=zr=|z| are 11 and 22. Both values are positive and thus valid. The sum of all possible values of z|z| is 1+2=31+2=3.