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Question: Consider a hollow sphere with centre at origin. find the distance of centre of mass of 1/4 th of the...

Consider a hollow sphere with centre at origin. find the distance of centre of mass of 1/4 th of the hollow sphere from origin

A

R/8

B

R/4

C

R*sqrt(2)/8

D

R/2

Answer

The distance of the center of mass of 1/4th of the hollow sphere from origin is R28\frac{R\sqrt{2}}{8}.

Explanation

Solution

  • Explanation of the solution: The center of mass of a quarter hollow sphere (defined by 0ϕπ/20 \le \phi \le \pi/2, 0θπ0 \le \theta \le \pi) is calculated by integrating the position vector weighted by the mass element over the specified region. For a uniform hollow sphere of radius RR, the coordinates of the center of mass of the quarter sphere are (R/8,R/8,0)(R/8, R/8, 0). The distance from the origin is then found using the distance formula: d=Xcom2+Ycom2+Zcom2=(R8)2+(R8)2+02=R264+R264=2R264=R28d = \sqrt{X_{com}^2 + Y_{com}^2 + Z_{com}^2} = \sqrt{\left(\frac{R}{8}\right)^2 + \left(\frac{R}{8}\right)^2 + 0^2} = \sqrt{\frac{R^2}{64} + \frac{R^2}{64}} = \sqrt{\frac{2R^2}{64}} = \frac{R\sqrt{2}}{8}.