Question

Consider a function f:N→R, satisfying
$f(1)+2f(2)+3f(3)+⋯+xf(x)=x(x+1)f(x);x≥2 with f(1)=1.$
Then $\frac{1}{f(2022)} + \frac{1}{f(2028)}$ is equal to $

• A. 8100
• B. 8400
• C. 8000
• D. 8200

Answer 1

Answer: (A)

8100

Answer 2

The Correct Option is (A): 8100