Consider a equation P(x)= ax2 + bx + c =0. If a,b,c ∈ A, we... | Mathematics | SolveeIt | Solveeit

Today, August 24

Question

Consider a equation P(x)= ax2 + bx + c =0. If a,b,c ∈ A, were A = {1, 2, 3, 4, 5, 6} . Then the probability that P(x) has real and distinct roots?

A

$\frac{1}{4}$

B

$\frac{1}{16}$

C

$\frac{25}{108}$

D

$\frac{19}{108}$

Answer

$\frac{19}{108}$

Explanation

Solution

The Correct answer is option is (D) : $\frac{19}{108}$