Question
Question: Consider a curve ax<sup>2</sup> + 2hxy + by<sup>2</sup> = 1 and a point P not on the curve. A line d...
Consider a curve ax2 + 2hxy + by2 = 1 and a point P not on the curve. A line drawn from the point P intersects the curve at points Q and R. If the product PQ. PR is independent of the slope of the line, then the curve is
A pair of straight lines
A circle
A parabola
An ellipse or a hyperbola
A circle
Solution
Let us choose the fixed point P as the origin. Let us now choose any line through P making an angle q with + ve direction of the X- axis (see fig).
Any point on this line can be chosen as
(r cos q, r sin q) where r is the distance measured from P.
If this point must also lie on the given curve, then we have
r2(a cos2 q + h sin 2q + h sin 2q + b sin2 q) – 1 = 0 ... (i)
For any given q, therefore there will be two values of r.
If PQ and PR be the roots of equation (i), then we have
PQ. PR = – f(θ)1where f(q) = a cos2 q + h sin 2q + b sin2 q
Since f(q) is given to be independent of q, therefore using calculus, we have
dθdf= – 2 a sin q cos q + 2h cos 2q + 2b sin q cos q = 0
i.e. (b – a) sin 2q + 2h cos 2q = 0 ... (ii)
Identically. (The word identically here implies, true for every value of q).
Equation (ii) will be identically true if and only if a = b and
h = 0
which therefore proves that the given curve must be circle.