Question

Consider a conical region of height h and base radius R with its vertex at the origin. Let the outward normal to its base be along the positive z-axis, as shown in the figure. A uniform magnetic field, $\overrightarrow{B}=B_0\hat{z}$ exists everywhere. Then the magnetic flux through the base ($\Phi_b$) and that through the curved surface of the cone ($\Phi_c$) are

• A. $\Phi_b=B_0\pi R^2;\Phi_c=0$
• B. $\Phi_b=-\frac{1}{2}B_0\pi R^2;\Phi_c=\frac{1}{2}B_0\pi R^2$
• C. $\Phi_b=0;\Phi_c=-B_0\pi R^2$
• D. $\Phi_b=B_0\pi R^2;\Phi_c=-B_0\pi R^2$

Answer 1

Answer: (D)

$\Phi_b=B_0\pi R^2;\Phi_c=-B_0\pi R^2$

Answer 2

The correct answer is (D) : $\Phi_b=0;\Phi_c=-B_0\pi R^2$