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Question

Physics Question on Thermodynamics

Consider a classical ideal gas of N molecules in equilibrium at temperature T. Each molecule has two energy levels, -∈ and ∈. The mean energy of the gas is

A

0

B

Ntanh(kBT)N\isin\tan h(\frac{\isin}{k_BT})

C

Ntanh(kBT)-N\isin\tan h(\frac{\isin}{k_BT})

D

2\frac{\isin}{2}

Answer

Ntanh(kBT)-N\isin\tan h(\frac{\isin}{k_BT})

Explanation

Solution

The correct answer is (C) : Ntanh(kBT)-N\isin\tan h(\frac{\isin}{k_BT})