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Question

Physics Question on laws of motion

Consider a car moving on a straight road with a speed of 100m/s100\, m/s. The distance at which car can be stopped, is : [μk=0.5][\mu_k = 0.5]

A

800m800\,m

B

1000m1000\,m

C

100m100\,m

D

400m400\,m

Answer

1000m1000\,m

Explanation

Solution

s=v22μkg=100×1002×0.5×10s=\frac{v^{2}}{2\mu\,_{k}g}=\frac{100\times100}{2\times0.5\times10} =100×1005×2=1000m=\frac{100\times 100}{5\times2}=1000\,m