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Question

Physics Question on System of Particles & Rotational Motion

Consider a body, shown in figure, consisting of two identical balls, each of mass M connected by a light rigid rod. If an impulse J = Mv is imparted to the body at one of its end, what would be its angular velocity ?

A

v/L

B

2v/L

C

v3L

D

v/4L

Answer

v/L

Explanation

Solution

Let ω\omega be the angular velocity of the rod. Applying, angular impulse = change in angular momentum about centre of mass of the system
j.L2=Icωj.\frac{L}{2}=I_c\omega
(Mv)(L2)=(2)(ML24)ω\therefore (Mv)\bigg(\frac{L}{2}\bigg)=(2)\bigg(\frac{ML^2}{4}\bigg)\omega
ω=vL\therefore \omega=\frac{v}{L}