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Question

Physics Question on Nuclei

Condiser the nuclear fission Ne20>2He4+C12{Ne^{20} -> 2 He^{4} + C^{12}} Given that the binding energy/nucleon of Ne20,He4{Ne^{20}, He^{4}} and C12{C^{12}} are, respectively, 8.03 MeV, 7.07 MeV and 7.86 MeV, identify the correct statement :

A

8.3 MeV energy will be released

B

energy of 12.4 MeV will be supplied

C

energy of 11.9 MeV has to be supplied

D

energy of 3.6 MeV will be released

Answer

energy of 11.9 MeV has to be supplied

Explanation

Solution

Ne20>2He4+C12{Ne^{20} -> 2He^{4} + C^{12}}
8.30×20        2×7.07×4+7.86×128.30 \times 20 \; \; \; \; 2\times 7.07 \times 4 + 7.86 \times 12
  EB=(BE)react(BE)product=9.72MeV\therefore \; E_B = (BE)_{react} - (BE)_{product} = 9.72 \, MeV