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Question: Concentrated hydrochloric acid is usually available at a concentration of \( \) 37.7 \( \) percent b...

Concentrated hydrochloric acid is usually available at a concentration of 37.7 percent by mass. The density of the solution is 1.19gml11.19gm{l^{ - 1}} . What is its molar concentration?

Explanation

Solution

We know that molarity is referred to as the number of moles (n) of solute present in one litre of the solution. To solve this question, we will first find the volume of the solution using the relation between mass, volume and density of the solution. Then, using the number of moles of solute and volume of the solution, we will find the molar concentration of the solution.

Complete Step By Step Answer:
We know that the molar concentration is referred to as the number of moles (n) of solute present in one litre of the solution. And the formula of the molarity is given as:
M = \dfrac{{n \times 1000}}{{V(mL)}}\\_\\_\\_\\_\\_(i)
In the question it is given that 37.7 percent hydrochloric acid by mass which can be interpreted as 37.7g of HCl present in the 100g of the solution. Now, to find the molar concentration, we will have to find the volume of the solution using the formula which is given as:
Volume=massdensityVolume = \dfrac{{mass}}{{density}}
Here, density is given as 1.19gml11.19gm{l^{ - 1}} and the mass of the solution is 100g . Therefore the volume will be:
Volume=1001.19Volume = \dfrac{{100}}{{1.19}}
Volume=84.033mlVolume = 84.033ml
Therefore, volume of the solution is found to be 84.033ml.84.033ml.
Now, we have to find the moles of HCl and as we know that number of moles (n) of solute (HCl) can be found by dividing the given mass by the molecular mass of HCl. Now, the mass of Hydrochloric acid is given as 37.7g and the molecular weight of HCl is 36.5g . So, after putting the values in the formula, we will get:
n=37.736.5n = \dfrac{{37.7}}{{36.5}}
n=1.0328n = 1.0328
Now, we will put the value of moles (n) and the volume of solution (i) in the equation (1), we will get:
M=1.0328×100084.033M = \dfrac{{1.0328 \times 1000}}{{84.033}}
M=12.29MM = 12.29M
Thus, the molar concentration of the solution will be 12.29M.12.29M.

Note:
There is one more concentration term which is known as normality and we should not get confused between the terms molarity and normality. Normality is defined as the number of moles of solute which are present in one kilogram of the solvent whereas molarity is referred to as the number of moles (n) of solute present in one litre of the solution.