Question

$Compute\ P(A|B), \ if P(B) = 0.5 \ and \ P(A∩B) = 0.32$

Answer 1

$Given:$
$P(B)=0.5$
$P(A∩B)=0.32$

∴ $P(A|B)=\frac {P(A∩B)}{P(B)}$

$P(A|B) =\frac {0.32}{0.50}$

$P(A|B) =\frac {32}{50}$

$P(A|B) =0.64$