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Question: Compressibility factor for an ideal gas will be equal to ______....

Compressibility factor for an ideal gas will be equal to ______.

Explanation

Solution

Hint: Compressibility factor is a quantity which relates a real gas to an ideal gas to determine its deviation from ideal behaviour.

Complete step by step answer: The change in density of a fluid due to application of pressure is called its compressibility. We consider both gases and liquids under fluids. It is the measure of how much a given gas shows deviation from ideal behaviour at similar temperature and pressure. It is denoted by ‘Z’.
But for an ideal gas
pV = nRT{\text{pV = nRT}}
Z = pVnRT{\text{Z = }}\dfrac{{{\text{pV}}}}{{{\text{nRT}}}}
So, for an Ideal gas the compressibility factor = 1.
The value of Z increases with rise in pressure and reduces with fall in temperature.

Additional information:
The ideal gas equation states that the product of pressure & volume of a gas bears a constant relation with the product of Universal gas constant and the temperature. pV = nRT{\text{pV = nRT}}
And compressibility factor Z = pVnRT{\text{Z = }}\dfrac{{{\text{pV}}}}{{{\text{nRT}}}}
If Z = 1, the gas is said to be ideal.
If  1{\text{Z }} \ne {\text{ 1}} the gas is said to be non-ideal.
If < 1{\text{Z }} < {\text{ 1}} the gas is said to have positive deviation from ideal behaviour and is less compressible.
If > 1{\text{Z }} > {\text{ 1}} the gas is said to have negative deviation from ideal behaviour and is more compressible.

Note: Compressibility factor is simply defined as the ratio of the molar volume of a real gas to the molar volume of an ideal gas at the same temperature and pressure.