Question

Compressibility factor for $1$ mole of a van der Waals' gas at $0^{\circ} C$ and $100$ atmospheric pressure is found to be $0.5$ the volume of gas molecules is :

• A. 2.0224
• B. 1.4666
• C. 0.8542
• D. 0.1119

Answer 1

Answer: (D)

0.1119

Answer 2

Compressibility factor $(Z)=\frac{P V}{n RT}$ For ideal gas $P V=n R T$ $\therefore Z=1$ For real gas $P V \neq n R T$ $\therefore Z \neq 1$ $0.5=\frac{100 \times V}{1 \times 0.82 \times 273}$ $V=0.1119\, L$