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Question: The value of the sum $|P_1 P_2|^2 + |P_1 P_3|^2 + \dots + |P_1 P_{10}|^2$ is...

The value of the sum P1P22+P1P32++P1P102|P_1 P_2|^2 + |P_1 P_3|^2 + \dots + |P_1 P_{10}|^2 is

Answer

20

Explanation

Solution

Let the vertices of the regular decagon be represented by complex numbers w1,w2,,w10w_1, w_2, \dots, w_{10}. We are asked to find the sum S=k=210w1wk2S = \sum_{k=2}^{10} |w_1 - w_k|^2. For a regular nn-gon centered at the origin with circumradius RR, the sum of the squared distances from one vertex to all other n1n-1 vertices is n(n1)R2n(n-1)R^2. In this case, n=10n=10. So the sum is 10(101)R2=10×9×R2=90R210(10-1)R^2 = 10 \times 9 \times R^2 = 90R^2.

However, a more direct theorem states that for a regular nn-gon inscribed in a circle of radius RR, the sum of the squared distances from any vertex to the other n1n-1 vertices is 2nR22nR^2. For n=10n=10, the sum is 2×10×R2=20R22 \times 10 \times R^2 = 20R^2.

If we assume the vertices are the 10th roots of unity, then R=1R=1. In this case, the sum is 20×12=2020 \times 1^2 = 20.