Question
Question: Ram and Shyam are walking on two perpendicular tracks with speed 3 $ms^{-1}$ and 4 $ms^{-1}$, respec...
Ram and Shyam are walking on two perpendicular tracks with speed 3 ms−1 and 4 ms−1, respectively. At a certain moment (say t = 0 s), Ram and Shyam are at 20 m and 40 m away from the intersection of tracks respectively, and moving towards the intersection of the tracks.
During the motion the magnitude of velocity of ram with respect to Shyam is

A
1 ms−1
B
4 ms−1
C
5 ms−1
D
7 ms−1
Answer
5 ms−1
Explanation
Solution
The velocity of Ram with respect to Shyam is given by vRS=vR−vS. Given vR=−3i^ and vS=−4j^, then vRS=−3i^+4j^. The magnitude of this relative velocity is:
∣vRS∣=(−3)2+(4)2=9+16=25=5ms−1.