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Question: Ram and Shyam are walking on two perpendicular tracks with speed 3 $ms^{-1}$ and 4 $ms^{-1}$, respec...

Ram and Shyam are walking on two perpendicular tracks with speed 3 ms1ms^{-1} and 4 ms1ms^{-1}, respectively. At a certain moment (say t = 0 s), Ram and Shyam are at 20 m and 40 m away from the intersection of tracks respectively, and moving towards the intersection of the tracks.

During the motion the magnitude of velocity of ram with respect to Shyam is

A

1 ms1ms^{-1}

B

4 ms1ms^{-1}

C

5 ms1ms^{-1}

D

7 ms1ms^{-1}

Answer

5 ms1ms^{-1}

Explanation

Solution

The velocity of Ram with respect to Shyam is given by vRS=vRvS\vec{v}_{RS} = \vec{v}_R - \vec{v}_S. Given vR=3i^\vec{v}_R = -3\hat{i} and vS=4j^\vec{v}_S = -4\hat{j}, then vRS=3i^+4j^\vec{v}_{RS} = -3\hat{i} + 4\hat{j}. The magnitude of this relative velocity is:

vRS=(3)2+(4)2=9+16=25=5ms1|\vec{v}_{RS}| = \sqrt{(-3)^2 + (4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \, ms^{-1}.