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Chemistry Question on Aldehydes, Ketones and Carboxylic Acids

Compounds AA and CC in the following reaction are CH3CHO>[(i)CH3MgBr][(ii)H2O](A)>[H2SO4,Δ](B)CH_3CHO {->[(i) CH_3MgBr][(ii)H_2O]} (A) {->[H_2SO_4, \Delta ]} (B) >[Hydroboration oxidation](C){->[{\text{Hydroboration oxidation}}]} (C)

A

identical

B

positional isomers

C

optical isomers

D

functional isomers

Answer

positional isomers

Explanation

Solution

CH3CHO>[(i)CH3MgBr][(ii)H2O]CH_{3}CHO { ->[{(i) CH_{3}MgBr}][{(ii) H_{2}O}] }
>[H2SO4][Δ]CH3?CHPropene (B)=CH2>[Hydroborationoxidation]CH3?CH2?CH2OHPropan-l-ol (C){ ->[{H_{2}SO_{4}}][{\Delta}] } \underset{\text{Propene (B)}}{{CH_{3}?CH}} =CH_{2}{ ->[Hydroboration \, oxidation]}\underset{\text{Propan-l-ol (C)}}{{CH_{3}?CH_{2}?CH_{2}OH}}