Question

Compound $X$ has the molecular formula ${C_3}{H_6}{O_3}$.
Heating $X$ under reflux with acidified ${K_2}C{r_2}{O_7}$ forms $H{O_2}CCOC{O_2}H$.
Reacting $X$ with $NaB{H_4}$ forms $HOC{H_2}CH(OH)C{H_2}OH$.
What is a possible structural formula for $X$ ?
1.$HOC{H_2}C{H_2}C{O_2}H$
2.$HOC{H_2}CH(OH)CHO$
3.$HOC{H_2}COC{H_2}OH$

A.1,2 and 3 are correct
B.1 and 2 only are correct
C.2 and 3 only are correct
D.1 only is correct

Answer 1

In the given question it is asked about the product that would form at the reaction of many different cases as mentioned. Among the given statements is statement three where the $NaB{H_4}$ is reacted and it gives contradicting statements. Now we know that it doesn’t react well with the acids so the one with the acid is the wrong one.

Complete step by step solution:
In the given question we have to find out the product we would be going to obtain when the reaction of the mentioned statements will take place and below that we are given three options that could be the possible outcomes of the reactions. This could be for any case.
Now we have to mention which one of the statements provides the wrong or not any outcome that we need from the example.
We can say that among the given options and the statements the $NaB{H_4}$ have the capacity to easily react and form compound with aldehydes and ketones whereas when it comes to the acids the reaction and the and formation is all sluggish, weak or not at all in many cases.
Thus we can say that the options $2$ and $3$ could be the possible structural formulas for the mentioned compound $X$.

Hence we can say that the right option would be option C.

Note: Sodium borohydride, also known as sodium tetrahydridoborate and sodium tetrahydroborate, is an inorganic compound with the formula $NaB{H_4}$. This white solid, usually encountered as a powder, is a reducing agent that finds application in chemistry, both in the laboratory and on an industrial scale.