Question

Compound A reacts with $NH _4 Cl$ and forms a compound B.

Compound B reacts with $H _2 O$ and excess of $CO _2$ to form compound $C$ which on passing through or reaction with saturated $NaCl$ solution forms sodium hydrogen carbonate Compound $A , B$ and $C$, are respectively.

• A. $CaCl _2, NH _4^{+},\left( NH _4\right)_2 CO _3$
• B. $CaCl _2, NH _3, NH _4 HCO _3$
• C. $Ca ( OH )_2, NH _3, NH _4 HCO _3$
• D. $Ca ( OH )_2, NH _4^{+},\left( NH _4\right)_2 CO _3$

Answer 1

Answer: (C)

$Ca ( OH )_2, NH _3, NH _4 HCO _3$

Answer 2

(A) Ca(OH)2​​+2NH4​ClΔ​ (B) 2NH3​​+CaCl2​+2H2​O
(B) NH3​​+H2​O+ (exc) CO2​​⟶ (C) NH4​HCO3​​
(c)NH4​HCO3​​+NaCl⟶NaHCO3​↓+NH4​Cl