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Question

Chemistry Question on p -Block Elements

Compound A reacts with NH4ClNH _4 Cl and forms a compound B Compound B reacts with H2OH _2 O and excess of CO2CO _2 to form compound CC which on passing through or reaction with saturated NaClNaCl solution forms sodium hydrogen carbonate Compound A,BA , B and CC, are respectively

A

CaCl2,NH4+,(NH4)2CO3CaCl _2, NH _4^{+},\left( NH _4\right)_2 CO _3

B

CaCl2,NH3,NH4HCO3CaCl _2, NH _3, NH _4 HCO _3

C

Ca(OH)2,NH3,NH4HCO3Ca ( OH )_2, NH _3, NH _4 HCO _3

D

Ca(OH)2,NH4+,(NH4)2CO3Ca ( OH )_2, NH _4^{+},\left( NH _4\right)_2 CO _3

Answer

Ca(OH)2,NH3,NH4HCO3Ca ( OH )_2, NH _3, NH _4 HCO _3

Explanation

Solution

Compound A reacts with NH4Cl and forms a compound B. Compound B reacts with H2O