Question

Compound ‘A’ reacts with to give ‘B’ which on treatment with $K C N$ followed by hydrolysis gave propanoic acid as the product. What is ‘A’

• A. Ethane
• B. Propane
• C. Ethyl chloride
• D. Ethyl alcohol

Answer 1

Answer: (D)

Ethyl alcohol

Answer 2

$\mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { OH } + \mathrm { PCl } _ { 5 } \rightarrow \mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { Cl } \xrightarrow { \mathrm { KCN } } \mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { CN }$