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Chemistry Question on Polarity of bonds

Compound A formed in the following reaction reacts with B gives the product C. Find out A and B.CH3−C≡CH+Na→A→BCH3−C≡C−CH2−CH2+NaBr(C) \text{CH}_3 - \text{C} \equiv \text{CH} + \text{Na} \xrightarrow{} \text{A}\xrightarrow{B} \text{CH}_3 - \text{C} \equiv \text{C} - \text{CH}_2 - \text{CH}_2 + \text{NaBr}(C)

A

Reac 3

B

Reac 2

C

Reac 1

D

Reac 4

Answer

Reac 1

Explanation

Solution

The given reaction suggests that sodium acetylide reacts with an alkyl halide to yield the final product. Here, compound A is formed as sodium acetylide:

CH3 – C ≡ CH + Na → CH3 – C ≡ CNa

Then, it reacts with compound B (1-bromopropane):

CH3 – C ≡ CNa + CH3CH2CH2Br → CH3 – C ≡ C – CH2CH2CH3 + NaBr