Question

Compound $A , C _5 H _{10} O _5$, given a tetraacetate with $AC _2 O$ and oxidation of $A$ with $Br _2- H _2 O$ gives an acid, $C _5 H _{10} O _6$ Reduction of $A$ with $HI$ gives isopentane The possible structure of $A$ is:

• A.
• B.
• C.
• D.

Answer 1

Answer: (C)

Answer 2

(i) Formation of tetraacetete with Ac2O means compound A has four -OH linkage.
Reduction of A with HI gives Isopentane i.e. molecule contains five carbon atom.
So , the correct option is (C) :