Question
Question: Complete the refracted ray in the flowing ray diagram  to the surface separating the two media. Now to understand how the refracted ray will behave in this case, we must first know Snell's law.
Now according to the Snell’s law,
ηi⋅sinθi=ηrsinθr
Where,
ηi is the refractive index of the medium where the incident ray lies,
θi is the angle between the normal and the incident ray,
ηr is the refractive index of the medium where the refracted ray lies, and
θr is the angle between the normal and the refracted ray. Thus from the Snell’s law, we can say that when a ray passes from a denser medium to rarer medium, the ray moves away from the normal, while when the ray passes from a rarer medium to a denser medium, the ray moves towards the normal.
Now, water has a density of 1000m3kg and turpentine oil has a density of 870m3kg, which is a rarer medium than water. Hence the ray moves away from the normal.
Thus the refracted ray of the following ray diagram is as follows:
Note:
Here, if the difference between the two refractive indices of the two medium is extremely high, unlike in the case as above, then the incident ray instead of refracting, it reflects. This will happen only if the angle of refraction is over 90 degrees, and the ray reflects. This phenomenon is known as total internal reflection, and this angle is known as critical angle.