Question
Question: Complete the reaction: RI+R′I
Mechanism :
This mechanism follows SN2 mechanism.
The formation of alcohol and alkyl iodide depends upon the group attached to the oxygen.
The order of alkyl groups favouring the SN2 mechanism at the iodide nucleophile to form the corresponding alkyl iodide (i.e., alkyl group in the place of R’) is as follows:
Tertiary alkyl group < Secondary alkyl group < Primary alkyl group.
So, the primary alkyl group is the first one to form alkyl iodide.
The first step is the protonation of oxygen and then the intermediate is formed. Then I− attack takes place (depending on the type of alkyl group) where the R’ bond breaks and forms corresponding alcohol and alkyl iodide.
So, let us see the reaction of given organic compound 2-ethoxy-3-methylpropane.
Hence the products obtained are 2-methylpropanol and ethyl iodide.
So, the right answer is option (c).
Note:
Ether undergoes combustion reaction, reacts with oxygen, and forms carbon dioxide and water. It is highly flammable and reacts with halogens like chlorine or bromine to form halogen-substituted ether that undergoes substitution reaction in the absence of sunlight.