Question

Complete the last column of the table

S. No.	Equation	Value	Say, whether the Equation No. is Satisfied. (Yes/ No)
(i)	x + 3 = 0	x = 3
(ii)	x + 3 = 0	x = 0
(iii)	x + 3 = 0	x = – 3
(iv)	x – 7 = 1	x = 7
(v)	x – 7 = 1	x = 8
(vi)	5x = 25	x = 0
(vii)	5x = 25	x = 5
(viii)	5x = 25	x = – 5
(ix)	$\frac{m}{3}=2$	m = – 6
(x)	$\frac{m}{3}=2$	m = 0
(xi)	$\frac{m}{3}=2$	m = 6

Answer 1

(i) x + 3 = 0
L.H.S. = x + 3
By putting x = 3,
L.H.S. = 3 + 3 = 6 ≠ R.H.S.
∴ No, the equation is not satisfied.

---

(ii) x + 3 = 0
L.H.S. = x + 3
By putting x = 0,
L.H.S. = 0 + 3 = 3 ≠ R.H.S.
∴ No, the equation is not satisfied.

---

(iii) x + 3 = 0
L.H.S. = x + 3
By putting x = - 3,
L.H.S. = - 3 + 3 = 0 = R.H.S.
∴ Yes, the equation is satisfied.

---

(iv) x - 7 = 1
L.H.S. = x - 7
By putting x = 7,
L.H.S. = 7 - 7 = 0 ≠
∴ R.H.S. No, the equation is not satisfied.

---

(v) x - 7 = 1
L.H.S. = x - 7
By putting x = 8,
L.H.S. = 8 - 7 = 1 = R.H.S.
∴ Yes, the equation is satisfied.

---

(vi) 5x = 25
L.H.S. = 5x
By putting x = 0,
L.H.S. = 5 × 0 = 0 ≠ R.H.S.
∴ No, the equation is not satisfied

---

(vii) 5x = 25
L.H.S. = 5x
By putting x = 5,
L.H.S. = 5 × 5 = 25 = R.H.S.
∴ Yes, the equation is satisfied.

---

(viii) 5x = 25
L.H.S. = 5x
By putting x = - 5,
L.H.S. = 5 × ( - 5) = - 25 ≠ R.H.S.
∴ No, the equation is not satisfied.

---

(ix) $\frac{m}{3}$= 2
L.H.S. = $\frac{m}{3}$
By putting m = - 6,
L.H.S. = $\frac{-6}{3}$= - 2 ≠ R.H.S.
∴ No, the equation is not satisfied. ≠ R.H.S.

---

(x) $\frac{m}{3}$ = 2
L.H.S. = $\frac{m}{3}$
By putting m = 0,
L.H.S. =$\frac{0}{3}$ = 0
L.H.S. = R.H.S.
∴ Yes, the equation is satisfied

---

(xi) $\frac{m}{3}$ = 2
L.H.S. =$\frac{m}{3}$
By putting m = 6,
L.H.S. = $\frac{6}{3}$ = 2
L.H.S. = R.H.S.
∴ Yes, the equation is satisfied