Question

Complete the given reaction.

$2Mn^{2 +} + 5\underline{(i)} + 8H_{2}O \rightarrow 2\underline{(ii)} + 10(\underline{iii)} + 16H^{+}$

(i) (ii) (iii)

• A. $SO_{4}^{2 -}$ $MnO_{4}^{-}$ $S_{2}O_{8}^{2 -}$
• B. $S_{2}O_{8}^{2 -}$ $MnO_{4}^{-}$ $SO_{4}^{2 -}$
• C. $MnO_{4}^{-}$ $S_{2}O_{8}^{2 -}$ $SO_{4}^{2 -}$
• D. $S_{2}O_{8}^{2 -}$ $SO_{4}^{2 -}$ $MnO_{4}^{-}$

Answer 1

Answer: (B)

$S_{2}O_{8}^{2 -}$ $MnO_{4}^{-}$ $SO_{4}^{2 -}$

Answer 2

:

Sol. $2Mn^{2 +} + 5S_{2}O_{8}^{2 -} + 8H_{2}O \rightarrow 2MnO_{4}^{-} + 10SO_{4}^{2 -} + 16H^{+}$