Question

Complete the following reactions:
1. $O{H_{2\left( g \right)}} + {M_m}{O_0}\xrightarrow{\Delta }$
2. $C{O_{\left( g \right)}} + {H_{\left( g \right)}}\xrightarrow{\Delta }$
3. ${C_3}{H_{8\left( g \right)}} + 3{H_2}{O_{\left( g \right)}}\xrightarrow{\Delta }$
4. $Z{n_{\left( s \right)}} + NaO{H_{\left( {aq} \right)}}\xrightarrow{\Delta }$

Answer 1

In the first reaction, the hydrogen is reacting with solid ${M_m}{O_0}$ in the presence of heat. In the given reactions, the chemical substances are transformed chemically into other chemical substances. And the species formed during the chemical reaction is known as a product. The reactant converts into products by passing them to a high energy transition state. And the chemical reactions are divided into different types, that is, synthesis, decomposition, addition, single replacement reaction and double replacement reaction.

Complete answer:

1. $0{H_{2\left( g \right)}} + {M_m}{O_0}\xrightarrow{\Delta }$
   In this reaction, o mole of gaseous hydrogen is reacting with solid ${M_m}{O_0}$, then there is a displacement reaction that takes place. The oxygen present in the ${M_m}{O_0}$ will attach to the hydrogen and there is a formation of water and the metal, M. The reaction can be written as,
   $0{H_{2\left( g \right)}} + {M_m}{O_0}\xrightarrow{\Delta }m{M_{\left( s \right)}} + 0{H_2}{O_{\left( l \right)}}$
2. $C{O_{\left( g \right)}} + {H_{\left( g \right)}}\xrightarrow{\Delta }$
   Here, one mole of carbon monoxide is reacting with hydrogen atoms in the presence of temperature, there is a formation of methanol. Let’s see the reaction;
   $C{O_{\left( g \right)}} + {H_{\left( g \right)}}\xrightarrow{\Delta }C{H_3}O{H_{\left( l \right)}}$
3. ${C_3}{H_{8\left( g \right)}} + 3{H_2}{O_{\left( g \right)}}\xrightarrow{\Delta }$
   When one mole of gaseous propane is reacting with three moles of water, in the presence of heat, there is a formation of three moles of carbon monoxide with seven moles of hydrogen gas. And the reaction can be written as,
   ${C_3}{H_{8\left( g \right)}} + 3{H_2}{O_{\left( g \right)}}\xrightarrow{\Delta }3CO + 7{H_{2\left( g \right)}}$
4. $Z{n_{\left( s \right)}} + NaO{H_{\left( {aq} \right)}}\xrightarrow{\Delta }$
   Here, one mole of zinc is reacting with sodium hydroxide under heat, there is a formation of sodium zincate by the elimination of hydrogen gas. And the reaction is,
   $Z{n_{\left( s \right)}} + NaO{H_{\left( {aq} \right)}}\xrightarrow{\Delta }N{a_2}Zn{O_{2\left( {aq} \right)}} + {H_{2\left( g \right)}}$

Note:
We have to know that during the chemical reaction, one or more chemicals are transformed into one or more other chemicals by occurring any of the chemical reactions like synthesis, decomposition, single replacement reaction and double replacement reaction. First we have to analyze the given reactant and the product and place it in any one of the categories of chemical reactions and find the product accordingly.