Question
Question: Complete the following reaction: \(Xe{F_6} + 2{H_2}O \to \)...
Complete the following reaction:
XeF6+2H2O→
Solution
Partial and controlled hydrolysis of XeF6 (xenon hexafluoride) gives xenon oxyflourides. XeF6 undergoes partial hydrolysis with 2 molecules of H2O to produce xenon dioxy difluoride (XeO2F2).
Complete step by step answer:
-XeF6 (xenon hexafluoride) is a fluoride of xenon , a noble gas. It is sp3d3 hybridised molecule and has a distorted octahedral shape. XeF6 reacts vigorously with water. The products of partial hydrolysis of XeF6 depends on the amount of water.
-If XeF6 is hydrolysed by 2 molecules of water, then the product will be xenon dioxydiflouride (XeO2F2).
XeF6(s)+2H2O(l)→XeO2F2(s)+4HF(aq)
-XeO2F2( xenon dioxydiflouride) are metastable colourless crystals. Its melting point is 31∘C. It decomposes into XeF2 (xenon difluoride) and O2 on standing, at room temperature. It is sp3d hybridised. In xenon dioxydifluoride the central atom will contain 4 bond pairs and a lone pair, due to the presence of the lone pair it has a see-saw shape. Due to the presence of a lone pair, XeO2F2 is polar in nature.
Note:
If the xenon hexafluoride is partially hydrolysed by one mole of water then XeOF4 (xenon oxytetrafluoride) will be formed.
XeF6(s)+H2O(l)→XeOF4(s)+2HF(aq)
Complete hydrolysis of xenon hexafluoride yields xenon trioxide.
XeF6(s)+3H2O(l)→XeO3(s)+6HF(aq)