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Question: Complete the following reaction: \(Xe{F_6} + 2{H_2}O \to \)...

Complete the following reaction:
XeF6+2H2OXe{F_6} + 2{H_2}O \to

Explanation

Solution

Partial and controlled hydrolysis of XeF6Xe{F_6} (xenon hexafluoride) gives xenon oxyflourides. XeF6Xe{F_6} undergoes partial hydrolysis with 22 molecules of H2O{H_2}O to produce xenon dioxy difluoride (XeO2F2)(Xe{O_2}{F_2}).

Complete step by step answer:
-XeF6Xe{F_6} (xenon hexafluoride) is a fluoride of xenon , a noble gas. It is sp3d3s{p^3}{d^3} hybridised molecule and has a distorted octahedral shape. XeF6Xe{F_6} reacts vigorously with water. The products of partial hydrolysis of XeF6Xe{F_6} depends on the amount of water.
-If XeF6Xe{F_6} is hydrolysed by 2 molecules of water, then the product will be xenon dioxydiflouride (XeO2F2)(Xe{O_2}{F_2}).
XeF6(s)+2H2O(l)XeO2F2(s)+4HF(aq)Xe{F_6}\,(s) + 2{H_2}O\,(l) \to Xe{O_2}{F_2}\,(s) + 4HF\,(aq)
-XeO2F2Xe{O_2}{F_2}( xenon dioxydiflouride) are metastable colourless crystals. Its melting point is 31C{31^ \circ }C. It decomposes into XeF2Xe{F_2} (xenon difluoride) and O2{O_2} on standing, at room temperature. It is sp3ds{p^3}d hybridised. In xenon dioxydifluoride the central atom will contain 4 bond pairs and a lone pair, due to the presence of the lone pair it has a see-saw shape. Due to the presence of a lone pair, XeO2F2Xe{O_2}{F_2} is polar in nature.

Note:
If the xenon hexafluoride is partially hydrolysed by one mole of water then XeOF4XeO{F_4} (xenon oxytetrafluoride) will be formed.
XeF6(s)+H2O(l)XeOF4(s)+2HF(aq)Xe{F_6}\,(s) + {H_2}O\,(l) \to XeO{F_4}\,(s) + 2HF\,(aq)
Complete hydrolysis of xenon hexafluoride yields xenon trioxide.
XeF6(s)+3H2O(l)XeO3(s)+6HF(aq)Xe{F_6}\,(s) + 3{H_2}O\,(l) \to Xe{O_3}\,(s) + 6HF\,(aq)