Question

Complete the following chemical equations:

$${\left( i \right){\text{ }}Cu + {H_2}S{O_4}\left( {conc.} \right) \to } \\\ {\left( {ii} \right){\text{ Xe}}{{\text{F}}_2} + {H_2}O \to }$$

Answer 1

A chemical reaction refers to a phenomenon which leads to the chemical transition of one type of chemical substance to another. Chemical reactions involve changes with reference to the electrons positioning in the formation as well as decomposition of chemical bonds that exist between the atoms, while no change occurs to the nuclei i.e. no alteration to the elements present. These chemical reactions undergo a chemical change, resulting in the formation of either one or more products that usually possess properties distinct from the reactants. The substances (one or more than one) initially participating in a chemical reaction are known as reactants.

Complete answer
There are five basic types of chemical reactions which are combination, single-displacement, double-displacement, decomposition and combustion. By analysing the reactants as well as products of the given reactions will allow you to place them into one of these different types of reactions. Few reactions can fit even into more than one category. Now, let us look at the given reactions one by one:
The first given reaction is
$(i){\text{ }}Cu + {H_2}S{O_4}\left( {conc.} \right) \to$
In this reaction, $Cu$ acts as a reducing agent while conc. ${H_2}S{O_4}$ behaves like an oxidising agent. Thus, $Cu$ does not displace the hydrogen from ${H_2}S{O_4}$ rather oxidised by the ${H_2}S{O_4}$. Now, this is not an acid-base reaction, but it is a redox reaction, as you see $Cu$ gets oxidised to $C{u^{2 + }}$ and ${H_2}S{O_4}$ gets reduced to $S{O_2}$. Thus, the complete reaction is written below:
$(i)Cu + 2{H_2}S{O_4}\left( {conc.} \right) \to 2{H_2}O + CuS{O_4} + S{O_2}$
The second given chemical equation is
$(ii){\text{ Xe}}{{\text{F}}_2} + {H_2}O \to$
$Xe{F_2}$ i.e. xenon difluoride is a colourless and volatile solid. $Xe{F_2}$ readily reacts with water (hydrolyses) to form xenon gas (i.e. $Xe$), oxygen gas (i.e. ${O_2}$) and hydrogen fluoride (i.e. $HF$). The complete chemical reaction is written below:
$(ii){\text{ }}Xe{F_2} + 2{H_2}O \to 2Xe + {O_2} + 4HF$

Note:
A balanced chemical equation simply obeys the law of conservation of mass. Balancing the chemical equations is a significant guiding principle in chemistry. A balanced chemical equation helps you to predict the amount of reactants required and the amount of products formed.