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Question: Compare the energies of two radiations \(E_{1}\) with wavelength 800 nm and \(E_{2}\)with wavelength...

Compare the energies of two radiations E1E_{1} with wavelength 800 nm and E2E_{2}with wavelength 400 nm.

A

E1=2E2E_{1} = 2E_{2}

B

E1=E2E_{1} = E_{2}

C

E2=2E1E_{2} = 2E_{1}

D

E2=−12E1E_{2} = - \frac{1}{2}E_{1}

Answer

E2=2E1E_{2} = 2E_{1}

Explanation

Solution

E1=hcλ1,E2=hcλ2E_{1} = \frac{hc}{\lambda_{1}},E_{2} = \frac{hc}{\lambda_{2}}

E1E2=hcλ1×λ2hc\frac{E_{1}}{E_{2}} = \frac{hc}{\lambda_{1}} \times \frac{\lambda_{2}}{hc} or E1E2=λ2λ1=400800\frac{E_{1}}{E_{2}} = \frac{\lambda_{2}}{\lambda_{1}} = \frac{400}{800}

E1E2=12\frac{E_{1}}{E_{2}} = \frac{1}{2} or E2=2E1E_{2} = 2E_{1}