Question
Question: Combustion of glucose takes place according to the equation: \[{{\text{C}}_{\text{6}}}{{\text{H}}_...
Combustion of glucose takes place according to the equation:
C6H12O6+6O2→6CO2+6H2O, ΔH = -72kcal
The energy required for the production of 1.6 g of glucose is [molecular mass of glucose is 180 g).
(A) 0.064 kcal
(B) 0.64 kcal
(C) 6.4 kcal
(D) 64 kcal
Solution
Hint: Use the value of molecular mass of glucose and relate it to value of heat of combustion provided in the question. As per the question, combustion of 180 g of glucose utilizes 72 kcal energy.
Complete step by step answer:
According to the question, complete combustion of energy has a latent heat equal to 72 kcal.
Since, Molar mass of glucose = 180 g/mol
Therefore, Energy required by 180 g glucose = 72 kcal
Energy required by 1 g glucose = 18072 kcal
Energy required by 1.6 g glucose = 18072 x 1.6 kcal = 0.64 kcal
Therefore, the answer is – option (b) – The energy required for the production of 1.6 g of glucose is 0.64 kcal.
Additional Information: “Combustion, or burning, is a high-temperature exothermic redox chemical reaction between a fuel and an oxidant, usually atmospheric oxygen, that produces oxidized, often gaseous products, in a mixture termed as smoke”.
Note: ΔH given in the question refers to latent heat.
“Latent heat is a thermodynamic quantity equivalent to the total heat content of a system. It is equal to the internal energy of the system plus the product of pressure and volume”. A negative heat of enthalpy means that the reaction is exothermic and is very feasible.