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Question: Coefficient of x<sup>99</sup> in the expansion of (x – 1) (x – 3) (x – 5) … (x – 199)...

Coefficient of x99 in the expansion of (x – 1) (x – 3) (x – 5) … (x – 199)

A

– 100

B

– 1000

C

– 10000

D

– 100000

Answer

– 10000

Explanation

Solution

Coefficient of x99 is equal to

= – (1 + 3 + 5 + ….. + 199)

= – 1002\frac { 100 } { 2 } [1 + 199]

= – 10000.