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Question

Mathematics Question on Binomial theorem

Coefficient of x11 x^{11} in the expansion of (1+x2)4(1+x3)7(1+x4)12(1 + x^2)^4 (1 + x^3)^7 (1 + x^4)^{12}

A

1051

B

1106

C

1113

D

1120

Answer

1113

Explanation

Solution

The correct answer is C:1113
The expression can be rewritten as a sum of terms involving various coefficients:
[(1+x2)4(1+x3)7(1+x4)12][ (1+x^2)^4 \cdot (1+x^3)^7 \cdot (1+x^4)^{12} ]
=(4C0+4C1x2+4C2x4+4C3x6+4C4x8)(7C0+7C1x3+7C2x6+7C3x9++7C7x21)]= (4C_0 + 4C_1 x^2 + 4C_2 x^4 + 4C_3 x^6 + 4C_4 x^8) \cdot (7C_0 + 7C_1 x^3 + 7C_2 x^6 + 7C_3 x^9 + \ldots + 7C_7 x^{21}) ]
[(12C0+12C1x4+12C2x8++12C12x48)][ \cdot (12C_0 + 12C_1 x^4 + 12C_2 x^8 + \ldots + 12C_{12} x^{48}) ]
The objective is to find the term that contains (x11)( x^{11} ) which corresponds to a power of ( x ) equal to 11. This can be achieved by selecting appropriate combinations of coefficients from each part=(4C07C112C2)+(4C17C312C0)+(4C27C112C1)+(4C47C11)]= (4C_0 \cdot 7C_1 \cdot 12C_2) + (4C_1 \cdot 7C_3 \cdot 12C_0) + (4C_2 \cdot 7C_1 \cdot 12C_1) + (4C_4 \cdot 7C_1 \cdot 1) ]
Calculating these products of coefficients:
=[(1766)+(4351)+(6712)+(17)=462+140+504+7=1113]= [(1 \cdot 7 \cdot 66) + (4 \cdot 35 \cdot 1) + (6 \cdot 7 \cdot 12) + (1 \cdot 7) = 462 + 140 + 504 + 7 = 1113 ]
So, the coefficient of (x11)( x^{11} ) in the given expression is 1113.
In a more natural language:
The expression is composed of three parts, each raised to a certain power, and it's required to determine the coefficient of (x11)( x^{11} ) in the expanded
form. This involves selecting appropriate coefficients from each part. After calculating the necessary products of coefficients, the coefficient of (x11)( x^{11} )is found to be 1113.