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Question

Mathematics Question on Statistics

Coefficient of variation of two distribution are 60 and 70, and their standard deviations are 21 and 16, respectively. What are their arithmetic means?

A

35, 22.85

B

22.85, 35.28

C

36, 22.85

D

35.28, 23.85

Answer

35, 22.85

Explanation

Solution

C.V.(1stdistribution)=60,σ1=21 {C.V. (1st\, distribution) = 60, \sigma_{1} = 21} C.V.(2nddistribution)=70,σ2=16 {C.V. (2nd \, distribution) = 70, \sigma_{2} = 16} Let x1ˉ\bar{x_1} and x2ˉ\bar{x_2} be the means of 1st and 2nd distribution, respectively, Then C.V.(1stdistribution)=σ1x1ˉ×100 {C.V. (1st\, distribution) = \frac{\sigma_{1}}{\bar{x_{1}}} \times 100 } 60=21x1ˉ×100\therefore \:\: 60 = \frac{21}{\bar{x_{1}}} \times 100 or x1ˉ=2160×100=35\bar{x_1} = \frac{21}{60} \times 100 = 35 and C.V.(2nddistribution)=σ2x2ˉ×100 {C.V. (2nd \,distribution) = \frac{\sigma_{2}}{\bar{x_{2}}} \times 100} i.e., 70=16x2ˉ×10070 = \frac{16}{\bar{x_2}} \times 100 or, x2ˉ=1670×100=22.85\bar{x_2} = \frac{16}{70} \times 100 = 22.85