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Question

Physics Question on thermal properties of matter

Coefficient of linear expansion of brass and steel rods are α1\alpha_1 and α2\alpha_2. Lengths of brass and steel rods are l1 l_1 and l2l_2 respectively. If (l2l1)(l_2 - l_1) is maintained same at all temperatures, which one of the following relations holds good ?

A

α1l22=α2l12\alpha_1 l^2_2 = \alpha_2 l_1^2

B

α12l2=α22l1\alpha_1^2 l_2 = \alpha_2^2 l_1

C

α1l1=α2l2\alpha_1 l_1 = \alpha_2 l_2

D

α1l2=α2l1\alpha_1 l_2 = \alpha_2 l_1

Answer

α1l1=α2l2\alpha_1 l_1 = \alpha_2 l_2

Explanation

Solution

Change in length for both rods should be same
Δ1=Δ2\Delta \ell_1 = \Delta \ell_2
1α1ΔT=2α2ΔT\ell_1 \alpha_1 \Delta T = \ell_2 \alpha_2 \Delta T
1α1=2α2\ell_1 \alpha_1 = \ell_2 \alpha_2