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Question: \(Cl_{2} + 2e^{-} \rightarrow 2Cl^{-};Eº = 1.36V\)of cell \(MnO_{4}^{-}\) (Where \(Mn^{2 +}\) for \(...

Cl2+2e−→2Cl−;Eº=1.36VCl_{2} + 2e^{-} \rightarrow 2Cl^{-};Eº = 1.36Vof cell MnO4−MnO_{4}^{-} (Where Mn2+Mn^{2 +} for CrO72−CrO_{7}^{2 -} is 2Cr3+2Cr^{3 +} for Fe3+Fe^{3 +} is Fe2+Fe^{2 +} is.

A
  • 1.25 V
B

Cl2Cl_{2}

C
  • 1.75 V
D
  • 4.0 V
Answer
  • 1.75 V
Explanation

Solution

Ecell=EAu3+/Auo−ENi2+/Nio=1.50−(−0.25)=1.75E_{\text{cell}} = E_{Au^{3 +}/Au}^{o} - E_{Ni^{2 +}/Ni}^{o} = 1.50 - ( - 0.25) = 1.75V.