Question

$Cl - P - Cl$ bond angles in $PCl_5$ molecule are

• A. $120^{\circ}$ and $90^{\circ}$
• B. $60^{\circ}$ and $90^{\circ}$
• C. $60^{\circ}$ and $120^{\circ}$
• D. $120^{\circ}$ and $30^{\circ}$

Answer 1

Answer: (A)

$120^{\circ}$ and $90^{\circ}$

Answer 2

$Cl - P - Cl$ bond angles in $PCl _{5}$ molecule are $120^{\circ}$ and $90^{\circ} . PCl _{5}$, having $s p^{3} d$ hybridised $P$ atom (trigonal bipyramidal geometry) has two types of bonds; axial and equatorial. These two types of bond have different bond lengths $1,2, 3$ - equatorial bonds and $4,5$ axial bonds