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Question: Circumcentre of the triangle whose vertices are (2, –1) , (3, 2) and (0, 3) is-...

Circumcentre of the triangle whose vertices are (2, –1) , (3, 2) and (0, 3) is-

A

(1, – 1)

B

(–1, 1)

C

(1, 1)

D

None of these

Answer

(1, 1)

Explanation

Solution

A ŗ (2, –1) B ŗ (3, 2) C ŗ (0, 3)

AB = 10\sqrt{10} , BC = 10\sqrt{10} ; CA = 20\sqrt{20}

Q AB2 + BC2 = CA2

\ DABC is right angled D, CA is Hypotenuse

mid point of hypotenuse CA is circumcentre M of DABC, M ŗ (2+02,−1+32)\left( \frac{2 + 0}{2},\frac{- 1 + 3}{2} \right)