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Question

Physics Question on Moving charges and magnetism

Circular loop of a wire and a long straight wire carry currents IcI _{ c } and IeI _{ e }, respectively as shown in figure. Assuming that these are placed in the same plane. The magnetic field will be zero at the centre of the loop when the separation HH is :

A

IeRIcπ\frac{ I _{ e } R }{ I _{ c } \pi}

B

IcRIeπ\frac{ I _{ c } R }{ I _{ e } \pi}

C

πIcIeR\frac{\pi I _{ c }}{ I _{ e } R }

D

IeπIcR\frac{ I _{ e } \pi}{ I _{ c } R }

Answer

IeRIcπ\frac{ I _{ e } R }{ I _{ c } \pi}

Explanation

Solution

Magnetic field at the centre OO of the loop of radius RR is given by B1=μ0Ic2RB _{1}=\frac{\mu_{0} I _{ c }}{2 R } where IcI_{c} is the current flowing in the loop. Magnetic field due to straight current carrying wire at a distance HH, i.e., at the point OO is given by B2=μ0Ie2πHB _{2}=\frac{\mu_{0} I _{ e }}{2 \pi H } For magnetic field to be zero at the centre of the loop, B1=B2B _{1} = B _{2} μ0Ic2R=μ0Ie2πH\frac{\mu_{0} I _{ c }}{2 R } =\frac{\mu_{0} I _{ e }}{2 \pi H } H=IeRπIc\Rightarrow H =\frac{ I _{ e } R }{\pi I _{ c }}