Question

Circle(s) touching X-axis at a distance 3 from the origin and having an intercept of length $2 \sqrt7$ on Y-axis is/are

• A. $x^2 + y2 - 6x + 8y + 9 = 0$
• B. $x^2 + y2 - 6x + 7y + 9 = 0$
• C. $x^2 + y2 - 6x - 8y + 9 = 0$
• D. $x^2 + y2 - 6x - 7y + 9 = 0$

Answer 1

Answer: (C)

$x^2 + y2 - 6x - 8y + 9 = 0$

Answer 2

PLAM
Here, the length of intercept on 7-axis is $\Rightarrow \, \, 2 \sqrt{ f^2} - c$
and if circle touches X-axis
\Rightarrow \hspace12mm g^2 = c
for $x^2 + y^2 + 2gx + 2fy + c = 0$
Here, \hspace5mm x^2 + y^2 + 2gx + 2fy + c = 0
passes through (3,0).
\Rightarrow \hspace12mm 9 + 6 g + c = 0 \hspace8mm ...(i)
\hspace20mm g^2 = c \hspace15mm ...(ii)
and \hspace15mm 2 \sqrt {f^2- c} = 2 \sqrt7
\hspace15mm f^2 - c = 7 \hspace15mm ...(iii)
From Eqs. (i) and (ii), we get
\hspace15mm g^2 + 6g + 9 = 0
\Rightarrow \hspace15mm (g + 3)^2 = 0
\Rightarrow \hspace15mm (g = - 3) and c = 9
\therefore \hspace15mm f^2 = 16 \Rightarrow f = \pm 4
\therefore \hspace15mm x^2 + y^2 - 6x \pm 8y + 9 = 0