Question

Circle having point (–1, 1) as its centre touches straight line

x + 2y + 9 = 0 then co-ordinate of point of contact are :

• A. (–7, –1)
• B. (–3, –3)
• C. (–3, 3)
• D. (0, 0)

Answer 1

Answer: (B)

(–3, –3)

Answer 2

Foot of perpendicular P(h, k)

$\frac{h + 1}{1}$ = $\frac{k–1}{2}$ = – $\frac{(–1 + 2 + 9)}{1 + 4}$

Ž h = – 3, k = – 3