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Question: cIf Var (x) = 8.25, Var (y) = 33.96 and Cov (x, y) = 10.2, then the correlation coefficient is...

cIf Var (x) = 8.25, Var (y) = 33.96 and Cov (x, y) = 10.2, then the correlation coefficient is

A

0.89

B

– 0.98

C

0.61

D

– 0.16

Answer

0.61

Explanation

Solution

rxy=Cov(x,y)Var(x)Var(y)=10.2(8.25)(33.96)=0.61r _ { x y } = \frac { \operatorname { Cov } ( x , y ) } { \sqrt { \operatorname { Var } ( x ) \cdot \operatorname { Var } ( y ) } } = \frac { 10.2 } { \sqrt { ( 8.25 ) ( 33.96 ) } } = 0.61 .