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Question: CH<sub>3</sub> –\(\underset{\begin{aligned} & | \\ & CH_{3} \end{aligned}}{CH}\)– CH = CH<sub>2</s...

CH3 –CH∣CH3\underset{\begin{aligned} & | \\ & CH_{3} \end{aligned}}{CH}– CH = CH2 + HBr → A (predominant), A is

A

B

C

D

None is correct

Answer

Explanation

Solution